Answers
The statistical software output for this problem is :
Test statistics 
= 13.2069
Degrees of freedom = 4
P-value = 0.0103
P-value is less than (or equal to) α .
C. reject the null
C. There is sufficient evidence to warrant rejection of the claim that all 5 categories are equally likely to be selected.
Chi-Square goodness-of-fit results: Observed: Oi Expected: All cells in equal proportion N DF Chi-Square P-value 58 4 13.206897 0.0103 Observed. Expected 10 11.6 5 11.6 21 11.6 14 11.6 8 11.6
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