## Answers

& Given, P(x) = x4_50²-6 = x 96x²+x²-6 = *? (22-6) +\(?6) P(x) = (a +1) (?6) (32+) (326) = 0 x²+1=0 (or x²-6=0 x² = 1 (or x = 6 (on x = ITG 1=EA o Zeros of P = 56, 56, i, - b ) p(a) = 2 + 1) (86) = (2+1) (222-US)) a ²b = 6tba.b) - 6309 (846) (2-50 = (2²=(-1)) (2 + 16) (a-ſo) = (2²-1²) (2-V6) (x+16) P(x) =(2+1% -1) (-16) (46)

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