Answers
Cp for oxygen = (7/2) R
Cv for oxygen = (5/2) R
Mass of oxygen 3kg 3 kg mole of oxygen X 1000gm 93.75 mole 32 gota/mot P = 2 bar (. ubar TI = 40°C 2313K Tez ? V = v Lis Process : constant volume (Isochanic food coes) LIS for iso choric Process Pressure X Temperaluse SO P2 PL Ta 4 bar X 313K 2bao » T2 = 626k 353°C /111) foo Q :- chatomic gas. Cp- FR = 2g. I mol-k 80 Cp= 29.1 KI Cp= 29.1 kJ Kmot-K Kmot K Cui 2 / R = B X 8.314 I mol-k 2 > G= 20.8 KI Komolk
AU= for isochosic process POV Ov=0 80 and 1) Су ДТ > SU= 93.75 70fx 2018.5.x (626–313) KX 1kJ mok 10007 su= 610.35 KJ su= 610.35KI Tron aloi25 kg (VII) Wa PAU IW= PV diagram: 4 bar- B R P 2bar V
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