y=2x+5
y = 2x + 3.5
y=−12x−4
y = 2x - 16.5
Answers
given that - - the line passes through The point P(5-6.5). & perpendicular to the given line let Slobe of the perbendlicular line is my Y=2015 slope of the m, = 2 Lets sloke of is m. perpenelicular one for the mutual Slope perbendicular line, the product of mm S- m2 -h The ean of bone - 9 -m, (2 - - 1. 3) (y - 465)) = (2-5) 4+ 2.5-65 = 12 - 4 y - 14-4 Ary y 24+3-55 Where mi= 2 Humlarly min2 = -1 7 m2 = - Ž the egn of perpendiculare Time - 1- (-6-5) = (X-5) y = -0.5 2e + 2.5 - 65 y = -0.521 a Ang Stoke wil y = -21-4 .) mi - - Timberly m.m2 = -1 m =2 3 Gu juube-4669) = 2(2015) 7 egr fline - - 220-0-65 39 = 22.
.
- 1615 Dry y = -2e-4 - fibre mia -2 Egyfleoey maz+1 = 12 -(-6.59 = = ( 2-5) y = x - 5 - 65 = 2 - 3 = + (2-83) Any y= 220-165 - m. = 2 me Egr of lone - (-65) - rz (2015) y = 2 ( 20-5) -65 - Ang y=-24-4 * CV> y = -4,2-9 - Mem, - 11 = 2 earchbv. ? Y-(-65) = m(215) - 2 (20-57 Y=24 - 165 ang
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