Answers
Hi there, from your provided example problem #3, i just followed those instructions.
Given Molecular Formula: C9H10O3
HDI = [2C + 2 + N -H -X] / 2 = [(2 x 9) + 2 + 0 -10 -0)] / 2 = 5
Hence HDI = 5
1H NMR: p-substituted Ar at 7.14-7.37 ppm, phenolic -OH proton at 6.68 ppm, broad singlet, benzoate CH3 group at 3.60 ppm, benzyl methylene group (-CH2-) proton at 3.50 ppm
13C NMR: carbonyl C at 171.00 ppm (ester), ester methyl -CH3 at 52.24 ppm, benzylic CH2 at 41.10 ppm, 4 remaining signals are Ar carbons, two of which are quaternary, typical of a p-substituted ring
Compound name is methyl (p-hydroxyphenyl)acetate (IUPAC name: methyl 2-(4-hydroxyphenyl)acetate)
NMR assignments:
Hope this helped you!
Thank You So Much!
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ОН
HNMR CNMR (B) HA (C) H0 HO- -0- -CH2-C- (E) 6 0-CH, 10) ng (BH HIA Assign ppm Assign. Shift (ppm) 7.36 7.15 6.68 Hem MUAH 171.00 157.89 130.87 125.90 116.24 52.24 41.10 3.6
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