1 answer

What values for #theta# for #( 0 ≤ theta ≤ 2pi)# satisfy the equation #3sin theta = sin theta -1

Question:

What values for #theta# for #( 0 ≤ theta ≤ 2pi)# satisfy the equation #3sin theta = sin theta -1 #?

Answers

The Solns. in #[0,pi]# are #7pi/6, and, 11pi/6#.

Explanation:

# 3sintheta=sintheta-1 rarr 2sintheta=-1 rArr sintheta=-1/2#

#:. sintheta=sin(pi+pi/6) rArr theta=7pi/6#.

Also, #sintheta=-1/2=sin(2pi-pi/6) rArr theta=11pi/6#.

Thus, the Solns. in #[0,pi]# are #7pi/6, and, 11pi/6#.

.

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