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The Agouti gene determines coat colour in mice. We can call this gene "A" for Agouti, where A is dominant and a is recessive.
Heterozygous mice have yellow coats: So mice with "Aa" are Yellow.
Homozygous dominant mice have black coats: So mice with "AA" are black.
Homozygous recessive genotypes are lethal for mice: SO mice with "aa" will not survive.
In a population of 2000 mice, 1082 have Black coats (or AA genotypes).
(1082)/(2000)= proportion of .541
*Remember the Hardy Weinberg Equation (p2+2pq+q2=1) and p+q=1 always.
P will equal the square root of p2: √p2= √ (.541) = 0.74
So the frequency of the A allele is 0.74
Q will equal 1-p: 1-(.74)= 0.26
So the frequency of the a allele is 0.26
The 0.541 proportion is representative of the mouse population with Black coats, or AA population. The Homozygous dominant genotype is represented in the HW equation as p2. So, we can find p by square rooting p2, and q by manipulating the p+q=1 equation.
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