# Two parallel long (infinite for our purposes) wires are suspended by a system of thin strings...

###### Question:

Two parallel long (infinite for our purposes) wires are suspended by a system of thin strings of length L=3.2 cm each as illustrated in the figure below showing the plane perpendicular to the wires. These wires are part of the electric circuit and run the same (but unknown) current I in the opposite directions. We treat the current I algebraically assigning the positive values to the current running out of the screen towards us (hence, currents I and −I next to the wires' position in the figure). The wires are in the region of the uniform magnetic field B as shown with the magnitude B=1.75 G. As appropriate for the wires, their "weight" is quantified by the linear mass density, it is equal to 11 g/m.

The wires are found in mechanical equilibrium when each of the strings is at angle θ=7.45° from the vertical as shown in the figure. This equilibrium can be realized, however, for both directions of the current in the wires.

Find current I=I1 enabling the equilibrium when it is positive (I1>0):
I1= ______A.

Find current I=I2 enabling the equilibrium when it is negative (I2<0):
I2= _____ A.

Two parallel long (infinite for our purposes) wires are suspended by a system of thin strings of length L=3.2 cm each as illustrated in the figure below showing the plane perpendicular to the wires. These wires are part of the electric circuit and run the same (but unknown) current I in the opposite directions. We treat the current i algebraically assigning the positive values to the current running out of the screen towards us (hence, currents I and -I next to the wires' position in the figure). The wires are in the region of the uniform magnetic field B as shown with the magnitude B=1.75 G. As appropriate for the wires, their "weight" is quantified by the linear mass density, it is equal to 11 g/m. B a The wires are found in mechanical equilibrium when each of the strings is at angle 0=7.45° from the vertical as shown in the figure. This equilibrium can be realized, however, for both directions of the current in the wires. Find current I=11 enabling the equilibrium when it is positive (11>0): 11= A. Find current I=Iz enabling the equilibrium when it is negative (12<0): 12= A.

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