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Given that = 0.3 m R = 300 mm mw = 51 kg. Ky = radius of Gyration 158 kg Ky 300 mm = 0.3 m m = 155 kg 2522 Nim.
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Spring potential energy love) { K 12 x will become double of locd fall. n = 2x so mm loc mm colm i Dve = į (2822) (0.12 = 1261 J - © Goavitational P.E lovg) =-(mwtm) gh --(54+158) (9.41)(0.05) Ang =-102051 J KE of wheel (OT) - 4 m, v2 + £ 12 m = mwim Iemk2 Ź (81+ 258) v2+ ] ( S1) v2 416-3)? (03)2 3 DT = 130 V2 Consider the balance ecuation. work energy OT + ove + Dug = 0 130 V2 + 12.61 102.51 = 0 V = 0.83 m/s
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