## Answers

n = 37

**D. The sample mean would not be considered unusual because there is a probability less than 0.05 of the sample mean being within this range.**

0 = 2.2 u = 12752 P(X < 12752 or X > 12755) = P(X < 12752) + P(X > 12755) = P(X < 12752) + (1 - P(X < 12755)) - 12752 - 12752 - + 1-P- - 12755 - 12752 =pl =p(z < 0.00) + (1 - p(z < 8.29)) From z score table = 0.50 + (1 - 1) = 0.50

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