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Geiven, pka = 3.70 Volume et cyanic Acid = 550 ml molarity of Cyanic Acid = 0.13M Volume of NaOH = 17 ml Molarity of Naot = loom milli moles of Cyanic Acid = 550 X0-13 = 71.5 m moles milli moles of NaOH = 17X1 I 17 m moles So, after bitration there will be (7105-17) = 54.5 m moles of Cyanic Aud remain. Also, 17 m moles of salt of Cyanic Acid will form . 30, it will form an Acidic Buffer solution. - of pH = 3.70 + log ( 1121 ) pH = 3.19 So, I pH = 3.19
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