1 answer

The manufacturer of hardness testing equipment uses stool-ball inderters to penetrate metal that is being tested....

Question:

The manufacturer of hardness testing equipment uses stool-ball inderters to penetrate metal that is being tested. However, th

indenters, it is suspected that the two methods will produce different hardness readin indenters on each specimen and compare
The manufacturer of hardness testing equipment uses stool-ball inderters to penetrate metal that is being tested. However, the manufacturer thinks it would be better to use a diamond indenter so that all types of metal can be tested. Because of differences between the two types of indenters, it is suspected that the two methods will produce different hardness readings. The metal specimens to be tested are large enough so that two Indentions can be made. Therefore, the manufacturer ses both indenters on each specimen and compares the hardness readings Construct a 95% confidence interval to judge whether the two indeters resut in different measurements Note: A normal probably plot and boxplot of the data indicate that the differences are approximately normally distributed with no outiers Click the icon to view the datatable Construct a 98% confidence interval to judge whether the two indenters result in different monsurements, where the differences are computed as 'diamond minus tool ball. The lower bounds The upper bounds (Round to the nearest tenth as needed) State the appropriate conclusion. Choose the correct answer below. O There is insufficient evidence to conclude that the two indenters produce different hardness readings O There is sufficient evidence to conclude that the two indenters produce different hardness readings
indenters, it is suspected that the two methods will produce different hardness readin indenters on each specimen and compares the hardness readings. Construct a 95% that the differences are approximately normally distributed with no outliers. 1 Data Table er 2 3 4 5 6 7 8 9 Specimen 1 Steel ball 51 Diamond 53 57 70 o in 65 61 61 68 69 54 55 51 51 53 56 56 74 68 inde Print Done F5 F6 > F7 F8 $ %

Answers

Sample 1 Sample 2 Difference Sample 1 - Sample 2 51 53 -2 57 56 1 61 61 0 70 74 -4 68 69 -1 54 55 -1 65 68 -3 51 51 0 53 56 -(1) Null and Alternative Hypotheses The following null and alternative hypotheses need to be tested: Ho: up = 0 Ha: up 0 This

Lower bound = -2. 726

Upper bound = -0.163

Conclusion :

2nd option is correct.

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