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First find the sample mean. Mean: 4+8+9+10+...+7+7 50 = 6.32 Then, the standard deviation is, s= {(x-7) = 150-, [(4-6.32) +(8-6.32) +__+(7-6.32)] = 3.0132
Therefore, the 95% confidence interval for the mean is, 6.32–2.01( 39382) < 2 <6.32+201 (3 0582) [Using t table, tog = 2.01] 6.32 -0.8566< u <6.32 +0.8566 5.46<u<7.18
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