HgI+Answers
[HgI42-] = 0.053 M
[I-] = 4.8 M
[Hg2+] = 1.0 x 10-30 M
Explanation
Overall equation : Hg2+ + 4 I- HgI42-
Overall K = (K1) * (K2) * (K3) * (K4)
Overall K = (1.0 x 108) * (1.0 x 105) * (1.0 x 109) * (1.0 x 108)
Overall K = 1.0 x 1030
initial moles Hg2+ = 0.053 mol
initial moles I- = 5.00 mol
moles HgI42- formed = initial moles Hg2+
moles HgI42- formed = 0.053 mol
moles I- consumed = 4 * (initial moles Hg2+)
moles I- consumed = 4 * (0.053 mol)
moles I- consumed = 0.212 mol
moles I- remaining = (initial moles I-) - (moles I- consumed)
moles I- remaining = (5.00 mol) - (0.212 mol)
moles I- remaining = 4.788 mol
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