1 answer

The answer should be Pb=18.41 KPa For the inclined-leg of the mercury manometer of Fig. 1-2,...

Question:

For the inclined-leg of the mercury manometer of Fig. 1-2, the pressure in pipe A is 15 kPa. The fluid in A has a specific gr

the answer should be Pb=18.41 KPa

For the inclined-leg of the mercury manometer of Fig. 1-2, the pressure in pipe A is 15 kPa. The fluid in A has a specific gravity of 0.9 and the fluid in B is water. What is the pressure in pipe B corresponding to the differential reading shown? (25 points) SG = 0.9 Water 100 mm 80 mm 50 mm Mercury Fig. 1-2

Answers

Pa = 15 kPa PA = 15roopa T A.S.U. 20:9 loomm gomm . .. 47eh , ресечту 1000 to = lsago alle som lu= esine= soxsinau Mercury lu

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