1 answer

Suppose 2.00 mol of an ideal gas of volume V =3.50m^3 at T = 300K .allowed...

Question:

Suppose 2.00 mol of an ideal gas of volume V =3.50
Suppose 2.00 mol of an ideal gas of volume V =3.50m^3 at T = 300K .allowed to expand isothermally to V = 7.00m^3 at T = 300K. Determine (a) the work done by heat added to the gas. and (c) the change in internal energy of the gas. (Ans: 3.6 times 10^3, J, 0, 3.6 times 10^3J)

Answers

work done =nrTln(v2/v1) = 2 x 300 x 0.0821 ln(7/3.5) =3.6 x 103J

U=Q-W

U=0 as change in temperature=0

change in internal energy =w =3.6 x 103J

.

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