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molarity = 5.42= n cont 5.06 (OH) M an=27.4252 moles of Naolt golt Weight 2-(27.4252 )*(409 – Machi 11.o 1097.008 grams Weight NaOH Litre 19.4 moles means 19.4M So I'litre (19.4) (40) 776 grams of Naut by mass but it is 50.1. Naoth solution so 6.1.2) Sol, it contains 6 388 grams of pure (1 litre) Nacht, reauind mass = 1097.000 1097.0089 reauind Volume = 3889/L 2.86423 Litres V. 2.82732 Litres
M(NaOH) x Varaolt = M (HNO3) * VANO HNO3 (0.616 M) x Viao H = (0.304)x (26.7mL) VNGUH NaulH = 13. 1766 2337 m Liu
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