1 answer

Standard Normal (2) Distribution n POSITIVE z Scor 18 old 06 07 E- (Rou 5239 5636...

Question:

Standard Normal (2) Distribution n POSITIVE z Scor 18 old 06 07 E- (Rou 5239 5636 5279 .5675 5438 5832 5871 6064 8968 .6406 6
POSITIVE z Scores bn: Cumulative Area from the LEFT 204 5359 5120 5160 5080 5478 5557 5239 5636 .6028 5753 RSS 5517 5910 6293
Use the sample data and confidence level given below to complete parts (a) through (d). A research institute pollasked respon
Standard Normal (2) Distribution n POSITIVE z Scor 18 old 06 07 E- (Rou 5239 5636 5279 .5675 5438 5832 5871 6064 8968 .6406 6772 .6443 .6808 .7157 .7486 5065 7086 7123 1. 0 2 Standard Normal (2) Distribution: Cumulative Area from the LEFT 03 04 05 00 5000 5040 5080 5120 5160 5 199 5398 5478 5517 5557 5790 .5910 5948 5987 6179 6217 6255 6298 .6331 6564 6591 6628 6664 .6700 6736 6915 6960 7019 7054 .7257 .7291 7224 7357 749 .7580 .7611 .7642 7673 7704 7995 BS 8186 8212 1238 8254 8289 3413 3430 3461 345 8500 3531 3643 3565 3708 3569 8907 eges 1914 9049 3066 9062 9090 9115 207 9265 9332 9345 9357 9394 9452 9474 9484 94951 505 9564 3673 9591 9964 3719 9726 9738 9747 ST72 3778 9783 .9798 SEBEBSB.SE 7910 7867 .7454 7764 8061 8315 8554 .7794 8078 8340 8577 3729 3770 8790 9131 9147 9292 5236 8279 9406 18 9515 9525 3713 96.56 9750 Print Done Click to select your answers) Type here to search
POSITIVE z Scores bn: Cumulative Area from the LEFT 204 5359 5120 5160 5080 5478 5557 5239 5636 .6028 5753 RSS 5517 5910 6293 5871 .6141 .5319 5714 .6108 .6480 .6844 5279 5675 .6064 .6443 .6808 .7157 .6517 5199 .5596 .5987 .6368 .6736 .7088 .7422 .7734 6255 5628 1985 5048 6331 6700 7064 7389 7704 7995 8264 8508 .6772 7123 7654 .6879 .7224 .7549 7324 7642 7486 7019 7357 7673 7367 7764 .7852 .7794 8078 7109 8061 8133 .7190 .7517 7823 .8106 .8365 .8599 .8810 1238 8289 8315 8340 o o oo 8212 3461 8485 8531 .8389 3621 8830 9015 8708 .8577 8790 8980 2007 85 8749 8944 9115 8770 8962 9131 8888 9066 3222 8997 9000 9162 910 292 9177 9019 5251 3255 9082 9236 3870 9484 5682 3006 9418 29 9515 9535 9545 9573 5495 501 671 .9608 9616 25 3394 9505 9599 9678 9744 9798 See 9706 9738 3732 9788 .9750 9008 .9756 9008 9761 9012 9817 Print Done Click to select your answer(s). e Type here to search
Use the sample data and confidence level given below to complete parts (a) through (d). A research institute pollasked respondents if they felt vulnerable to identity theft. In the poll, n=955 and x =526 who said "yes. Use a 90% confidence level Click the icon to view a table of z scores a) Find the best point estimate of the population proportion p. (Round to three decimal places as needed.) b) Identify the value of the margin of error E E- (Round to three decimal places as needed.) c) Construct the confidence interval [ <p < (Round to three decimal places as needed.) d) Write a statement that correctly interprets the confidence interval. Choose the correct answer below OA One has 90% confidence that the sample proportion is equal to the population proportion OB. There is a 90% chance that the true value of the population proportion will fall between the lower bound and the upper bound OC One has 90% confidence that the interval from the lower bound to the upper bound actually does contain the true value of the population proportion OD 90% of sample proportions will between the lower bound and the upper bound Click to select youw ers O 9 TA .

Answers

we have given x= 526 , n = 955

a ) the best estimate of population proportion p is \hat{p} =\frac{x}{n}   

\hat{p} =\frac{526}{955} = 0.551

b ) margin of Error (E) = z\sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

from z table z at 90% confidence level is 1.64

M.E. = 1.64\sqrt{\frac{0.551(1-0.551)}{955}}

M.E. = 0.026

c ) the 90 % Ci for p = \hat{p}\pm M.E.

= 0.551 \pm 0.026

= (524,577)

90\%90% confidence interval for the population proportion is 0.524<p<0.577

d ) option B is true

.

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