## Answers

If the person freely hanges to the spring theelongationof the spring be = xlet m be the mass of the person ,mg = -kxk = force constant of the springwhen the spring is compressed to x to project himthe kientic energy transfeered to the personmv^2 / = kx^ / 2 (spring potentil energy )from the above equation we can subject out velocityvwhen ihe is projectred with velocity v at an angleθ with the horizantal the range of the projectile willbeR = v^2 * sin2θ / gand the maximum heigh reached by the personH =v^2*sin^{2}θ / 2gfrom the above relations we can solve for the requiredparameters ..

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