1 answer

Solve question one the drawing is right beside it and the key answer I want explaining...

Question:

Problem 1: Find the support reactions and draw the moment diagram for the beam: (CLO #2) 15kN/m Find support moment: 20x3-(15x3/2)+M-Mp-7.5kN-m. Static Moment: 15x3/8-16.875kN-m Ok MB Ra Rcv 15kN Rehx3-5x2-5x4-5x6 0 RG.hz 60/3-20kN =-Rah Ro.b 3 in Problem 2 Solve the truss forces at node A using (a) The method of Sections and (b) the method of Nodal Force Equilibrium n N P From equilibrium of Node G in y: FAO 15 (T) S kN From equilibrium of Node G In x: For 20(T) (b) Method of Joints (Nodes), NodeA Take part BDF: Moments about F FaBx3+5x2+5x4-0FAB (30/3)-10 (C) Take moments about B: FaFx2sin56.3+Forx3-5x2-5x40 FAF (10+20-20x3)/2/0.83-18kN (C) 20F40 For FBA Forsin56.3+150 For-15/sin56.3-18kN (C) 20-18cos56.3-FRA 0FRA 20-18cos56.3 10kN(C) Solve question one the drawing is right beside it and the key answer I want explaining step by step for the drawing and the forces found please
Problem 1: Find the support reactions and draw the moment diagram for the beam: (CLO #2) 15kN/m Find support moment: 20x3-(15x3/2)+M-Mp-7.5kN-m. Static Moment: 15x3/8-16.875kN-m Ok MB Ra Rcv 15kN Rehx3-5x2-5x4-5x6 0 RG.hz 60/3-20kN =-Rah Ro.b 3 in Problem 2 Solve the truss forces at node A using (a) The method of Sections and (b) the method of Nodal Force Equilibrium n N P From equilibrium of Node G in y: FAO 15 (T) S kN From equilibrium of Node G In x: For 20(T) (b) Method of Joints (Nodes), NodeA Take part BDF: Moments about F FaBx3+5x2+5x4-0FAB (30/3)-10 (C) Take moments about B: FaFx2sin56.3+Forx3-5x2-5x40 FAF (10+20-20x3)/2/0.83-18kN (C) 20F40 For FBA Forsin56.3+150 For-15/sin56.3-18kN (C) 20-18cos56.3-FRA 0FRA 20-18cos56.3 10kN(C)

Answers

Ar DORO 25 -B- 8-15132- t SFD 250 20. l S m. 2.ca)-탄→ Mo= 20嗲-5Ds) BMD 1333a0 13.125 KN. GP に5m M = 13.125 140m)

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