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Sods pts each) Patsy placed 2.6089 g of an unknown malachite mixture into a ble. The...

Question:

sods pts each) Patsy placed 2.6089 g of an unknown malachite mixture into a ble. The following are the data collected in the
sods pts each) Patsy placed 2.6089 g of an unknown malachite mixture into a ble. The following are the data collected in the lab: mit de Mass of crucible + mixture before heating: 25.4824 g Mass of crucible + mixture after heating: 25.2444 g Calculate the following ***BOX YOUR FINAL ANSWERS***): i. Mass of H2O + CO2 lost: low or Jam e nto total -botines 150619 25.48249 - 25.24449= 0.24059) OSM slo ateien ii. Moles of H2O + CO2 lost (molar mass of H20 = 18.01 g/mol; CO2 = 44.01 g/mol): 2405 iii. Moles of malachite in mixture: Santo Tolosi H2o, coif I mole maluchle I mole Hee, col 221.11 g/mol Tlmol 120, con lo 63.039 Imd malucht = 10.84369

Answers

MO Mass of tot Mass of malachito mixture before a ll heating - 2.6089 Mass of glass mass of malachite - 25.48 2. e4824 g Crucciu) Mass of mixture - 2.3709 g. after heating - rolar mass of malachite - 221.12 g/mol This simples 221.12g of molachite = 1

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