Answers
a)P(ace of spades is one of sixteen cards) =16/52 =0.308
b) P(none of the 16 are ace of spades) =1-P(it is in rest of 36 cards) =1-36/51 =0.294
c) P(Ace of spade in one of 16 cards|not found in 10 draws) =((16/52)*(15/16)10)/((16/52)*(15/16)10+(36/52)*110)
=0.189
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