Answers
The balanced reaction is as follows:
N2H4(aq) + O2(g) N2(g) + 2H2O(l)
Mass of N2H4 = 3.05 g
Temperature(T) = 295 K
Pressure(P) = 1.00 atm
Determine the moles of N2H4 as follows:
Molar mass of N2H4 = 32.0452 g/mol
= 3.05 g N2H4 x ( 1 mol N2H4 / 32.0452 g N2H4)
= 0.09518 mol N2H4
Use the moles of N2H4 and the mole ratio from the balanced chemical reaction. Determine the moles of N2 as follows:
= 0.09518 mol N2H4 x ( 1 mol N2 / 1 mol N2H4)
= 0.09518 mol N2
The ideal gas law equation is as follows:
PV = nRT
Rearrange the formula for volume as follows:
V = nRT /P
V = (0.09518 mol x 0.08206 L.atm/mol.K x 295 K) / 1 atm
V = 2.304 L
Thus, the theoretical yield of N2 gas is 2.304 L
Determine the percentage yield as follows:
Experimental yield of N2 = 0.950 L
Theoretical yield of N2 = 2.304 L
Percent yield = [ Experimetnal yield / Theoretical yield] x 100 %
Percent yield = [ 0.950 L / 2.304 L] x 100 %
Percent yield = 41.2 %
Thus, the percent yield of the reaction will be 41.2 % [3 S.F].
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