1 answer

Question: Prelab Question #2: A student has weighed out 850 mg of 1-pentanol in 50 mL...

Question:

Prelab Question #2: A student has weighed out 850 mg of 1-pentanol in 50 mL volumetric flask and prepared four standard solut

Instructional Videos to Watch before Lab Fundamentals of GC EXPERIMENTAL PROCEDURE Preparation of Solutions. Get a glassware
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and unkcaiculate peak area ratio of I pentanol to internal standard for all sandard solutions. Take average of two measuremen
Question:
Prelab Question #2: A student has weighed out 850 mg of 1-pentanol in 50 mL volumetric flask and prepared four standard solut
Prelab Question #2: A student has weighed out 850 mg of 1-pentanol in 50 mL volumetric flask and prepared four standard solutions as described in this procedure. Calculate concentrations of 1-pentanol in mg/mL in each of these solutions.
Instructional Videos to Watch before Lab Fundamentals of GC EXPERIMENTAL PROCEDURE Preparation of Solutions. Get a glassware bin from your TA. Rinse five 10 .00 mL volumetric flasks with 2-propanol (isoproponal) to remove any al cohols remaining in the nprevious usage. Rinse a 50.00 mL volumetric flask with acetone and dry it by allowing it to drain and stand or by passing a slight stream of air through the flask. Rinse the pipet and buret at the time of use with small portions of the solution to be measured. Number the 10.00 mL volumetric flasks from 1 to 5. Give a 10.00-mL flask labeled 5 to the instructor to obtain the unknown, a mixture of I-pentanol and this number in your lab notebook. 2-propanol. Your TA must give you an unknown number. Record Weigh accurately the dry 50.00-mL volumetric flask with cap in. Pipette about 1 ml of 1-pentanol (N-amyl alcohol) into the flask and close immediately with the cap. (1 of 1 pentanol is highly volatile, it may evaporate if not capped). Weigh the flask and contents. Dilute immediately to the mark with 2-propanol and mix well. Rinse and fill the 10-mL buret with this solution (the standard solution of I-pentanol). Prepare all solutions in the hood of 1216 Gilman Hall. Ask your TA for assistance. 102
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and unkcaiculate peak area ratio of I pentanol to internal standard for all sandard solutions. Take average of two measurements of each solution. Step 3. Make a table showing all results of step 1 and 2. YOU MUST RECORD ALL CALCULATIONS IN YOUR LAB NOTEBOOK. Step 4. Prepare a standard calibration curve by plotting peak area ratios agains 1-pentanol concentrations (unit: mg/mL). Use Excel. The computers located in 1215 Gilman are loaded with these programs for your calculation. YOU MUST ATTACH A COPY OF THIS STANDARD CALIBRATION PLOT IN YOUR LAB NOTEBOOK. Step 5. Use the slope and intercept from the regression program of the standard calibration curve to calculate the amount of 1-pentanol (in mg) in the unknown obtained from your TA. Step 6. Submit the result reporting form showing the amount of 1-pentanol (in mg) in your unknown on Canvas.
Prelab Question #2: A student has weighed out 850 mg of 1-pentanol in 50 mL volumetric flask and prepared four standard solutions as described in this procedure. Calculate concentrations of 1-pentanol in mg/mL in each of these solutions.

Answers

According to the lab procedure ,

We have to make standard solution in these steps :

Step 1. Weigh accurately the dry 50 ml volumetric flask with cap.

Step 2. Pipette 1ml of 1-pentanol into flask.

Step 3. Weigh the flask with contents.

Step 4. Dilute with 2 propanol until solution become 50 ml

Step 5.

Mixing and filling the 10 ml burette with this solution

Now, when we know that weight of flask with contents = 850mg ( 1-pentanol in 50 ml flask ) we already done the step 3

Now we have the 50 ml solution in which 850 mg is 1- pentanol rest is 2-propanol

Concentration of this bulk solution = 850mg / 50ml = 17 mg/ml

Now , we need to prepare 5 solution , according to the given conditions

Solution no. 1

Standard stock ( burette ) or the solution we prepared = 0.5 ml

Internal standard = 0.2 ml

Amount of 1-pentanol in mg in solution 1 = concentration of bulk solution * vol of standard solution

= 17 mg/ml * 0.5 ml = 8.5 mg

Net volume of solution = 0.5 + 0.2 = 0.7 ml

Concentration of 1- pentanol in solution 1 = 8.5 mg / 0.7 ml = 12.143 mg/ml (answer)

Similarly for other 4 solutions,

For solution 2:

Solution we prepared = 1.0 ml

Internal standard = 0.2 ml

Net volume of solution = 1.0 + 0.2 = 1.2 ml

Amount of 1-pentanol in solution 2 = 17 mg/ml * 1.0 ml = 17 mg

Concentration of 1-pentanol in solution 2 = 17mg/1.2ml = 14.166 mg/ml (answer)

Solution no. 3 :

Solution we prepared = 1.5 ml

Internal standard = 0.2 ml

Net volume of solution = 1.7 ml

Amount of 1-pentanol in solution 3 = 17 mg/ml * 1.5 ml = 25.5 mg

Concentration of 1-pentanol in solution 3 = 25.5 mg / 1.7 ml = 15 mg/ml ( answer )

Solution 4:

Solution we prepared = 2 ml

Internal standard = 0.2 ml

Net volume of solution = 2+0.2 = 2.2 ml

Amount of 1-pentanol in solution 4 = 17 mg/ml * 2 ml = 34 mg

Concentration of 1-pentanol in solution 4 = 34 mg / 2.2 ml = 15.45 mg/ml ( answer )

Solution 5 :

Solution we prepared = 0 ml

Internal standard = 0.2 ml

Concentration of 1- pentanol in solution = 0 mg / 0.2 ml = 0 mg/ml ( answer )

.

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