1 answer

Question 48 10 pts Row Mask (/Prefix) Interface Destination Network or Subnet Metric (Cost) Next- Hop...

Question:

Question 48 10 pts Row Mask (/Prefix) Interface Destination Network or Subnet Metric (Cost) Next- Hop Router 128.171.0.0 47 2

Question 48 10 pts Row Mask (/Prefix) Interface Destination Network or Subnet Metric (Cost) Next- Hop Router 128.171.0.0 47 2. G 1 2 255.255.0.0 (116) 255.255.255.0 (124) 172.30.33.0 0 1 Local 3 60.168.6.0 255.255.255.0 (124) 12 2 G 4 123.0.0.0 255.0.0.0 (8) 33 2 G 5 172.29.8.0 34 1 F 255.255.255.0 (124) 255.255.255.0 (124) 6 172.40.6.0 47 3 H 7 128.171.17.0 55 3 H 00 172.29.8.0 20 3 H 9 172.12.6.0 23 1 TI 10 172.30.12.0 255.255.255.0 (24) 255.255.255.0 (124) 255.255.255.0 (124) 255.255.255.0 (124) 255.255.255.0 (124) 255.255.0.0 (116) 0.0.0.0 (10) 9 2 G 11 172.30.12.0 3 3 H 12 60.168.0.0 16 2 G 13 0.0.0.0 5 3 H If a packet arrives with destination IP addresses 128.171.17.5 Which interface the router should choose? (list all the rows matches, pick the one, explain)

Answers

Given,

Destination IP address: 128.171.17.5

Anding with Subnet mask gives destination network or subnet.

ANDing with 255.255.0.0 (/16)

10000000.10101011.00010001 .00000101 ==>128.171.17.5

11111111.11111111.00000000.00000000 ==>255.255.0.0

------------------------------

10000000.10101011.00000000.00000000 ==>128.171.0.0

------------------------------

ANDing with 255.255.255.0 (/24)

10000000.10101011.00010001 .00000101 ==>128.171.17.5

11111111.11111111.11111111.00000000 ==>255.255.255.0

------------------------------

10000000.10101011.00010001 .00000000 ==>128.171.17.0

------------------------------

ANDing with 255.0.0.0 (/8)

10000000.10101011.00010001 .00000101 ==>128.171.17.5

11111111.00000000.00000000.00000000 ==>255.0.0.0

------------------------------

10000000.00000000.00000000.00000000 ==>128.0.0.0

------------------------------

Therefore, It matches with the following destination networks:

  • 128.171.0.0
  • 128.171.17.0

Hence, Router will choose interface 3 and route the packet to destination address or subnet 128.171.17.0 because it has the longest prefix match with it compared to 128.17.0.0

.

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