## Answers

m² Given, rotational inentia I = 3.77 kg) Tanque q = 67.2979.27+) Nm At t= 15 angular momenturi 1,=5.70 kgm/s Let angular momentum at tq=sis L₂ We know = IDF an JL "th 2 or, Ela 2 Tonque a = I x L = Iw I dw = q at. dL-Idw da = ſati Integrating from ti to tz weget sem South ( 7.29+9.294) dt. Lg -4 7.29 (t2-t)) +9.27 or-5. 70 + L2 = 7.29 (3-1) + 9.27 +9:23 (32-2) or, -5.70 +L2 = 14058 + 37.08 an LL 57.36 kgm/s Angulan momentum at t=3sis La = 57.36 kym?/s وا 5.70 +14.58 +37.08 CSScanned with CamScanner

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