QUESTION 1 0.5 points Save Answer The weak acid, HX, is neutralized by sodium hydroxide as...

1. Assuming the density of solution=1.00 g/mL

Volume of solution=Volume of HX+Volume of NaOH

=50.0 mL+50.0 mL=100.0 mL

Mass of solution=Volume x Density

=100.0 mL x 1.00 g/mL

=100.0 g

As the temperature of the calorimeter increases by 1.79°C, this means heat released in the neutralisation reaction is absorbed by the calorimeter

Heat absorbed=Mass of solution x specific heat of solution x rise in temperature

=100.0 g x 4.184 J/g°C x 1.79°C=748.94 J

Number of moles of HX=Molarity x volume (L)

=0.500 M x 50.0 mL/1000 mL/L=0.025 mol

Number of moles of NaOH=Molarity x volume (L)

=0.500 M x 50.0 mL/1000 mL/L=0.025 mol

So HX and NaOH completely neutralise each other as number of moles of HX and NaOH are equal.

Enthalpy of neutralisation=-heat absorbed by the solution/number of moles of HX

=-748.94 J/0.025 mol=(-748.94 J/1000 J/kJ)/0.025 mol

=-29.96 kJ/mol

So Enthalpy of neutralisation=-29.96 (without units as asked in the question)