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Sol Lv = 100k.12 {RD { RL = 2k2 4u Given data NTP = -0-6v, kp= IMA/V² x=0, Ipg = 0.25mA, VSDQ = 1.5V- (a) First D.Canalysis of MOSFET Open circut all capacitor ve 0 Ro 100kr ERD ~ -uv Vo=0 Given Is = + kp (vs-1 VTpl) = 0.25mA = X IMA/V² (Us - 0.6)" VSG=Vs- Vy =) :5 m A = 1 MA/V² (vs - 0.6)2 =) (VS-06)² = .58² :) (vs-0-6) √ 5v2 . V to.707 v to 6v - 1.307 -0.107V at Vs =-0.107 V30 = to 0.107clvipl Transistor is off Hence Vs = 1.307 v
Vs = uv- Rs I Do -:Rs = 4v-1.3070 - Iog LV-1-307v 25mA - 10.772 * 2 Rs = 10.772K2 Given VSDQ = 1.5v V S D Q = Vs-Vo = 1.50 No= Vs - 1.5V = 1.307-1.5V = -0.1930 Vo = -4V+ Too Ro LV- 0.193 v = 15.228 KR Notu v . Ro - - 25mA Iog RD = 15.9228K2 (b) for small signal equivalent ground all doc Source S.C all cabautor
vo { Rulooka Im Vas ROLIRL Imate .267A = 0.0ims ROIR = 15.228K2 112k2 =1.76K2 (c) Rin = Po= looks | Rout= RolIRL = 1.76k2 Ar= -9m ľRD IIR() = -0.01 X 1.76k2 Av = -17.6 VV
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