1 answer

Point A is at #(3 ,7 )# and point B is at #(3 ,-4 )#. Point A is rotated #pi/2

Question:

Point A is at #(3 ,7 )# and point B is at #(3 ,-4 )#. Point A is rotated #pi/2 # clockwise about the origin. What are the new coordinates of point A and by how much has the distance between points A and B changed?

Answers

New coordinates of point A is #(-7,3)# and Distance between A and B changed by #1.1# unit.

Explanation:

#A(3,7) and B (3,-4)# . Clockwise rotation of point A is

#alpha=pi/2 :. # Counterclockwise rotation of point A is

#theta=2pi-alpha=2pi-pi/2=(3pi)/2#. New coordinates of

#A(x',y')# can be found by the fomula ,

#x'= xcos theta +ysin theta and y'= y cos theta - x sin theta#

#:.x'= 3*cos((3pi)/2)+7*sin((3pi)/2) = 0+(-7)=-7#

#x'= -7; y'= 7* cos((3pi)/2)- 3 * sin((3pi)/2) #

#= 7 * 0-3 *(-1)=3:. y'=3 :.

(x',y') = (-7,3)#

Distance between two points #(x_1,y_1) and (x_2,y_2)# is

#D= sqrt((x_1-x_2)^2+(y_1-y_2)^2)# . Orginal distance between

points #A(3,7) and B (3,-4)# is

#D_o= sqrt((3-3)^2+(7+4)^2)=sqrt 121= 11.0# unit.

New distance between points #A(-7,3) and B (3,-4)# is

#D_n= sqrt((-7-3)^2+(3+4)^2)=sqrt 149~~ 12.2# unit

Distance between A and B changed by #12.2-11.1=1.1# unit .

[Ans]

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