## Answers

Criven, find out the equation of the line tangent to the graph of x² + y²_quy zo at point (1,1) we know the equation of tangent, 2-а, m (x-xi) з 8-8, - dy (0-11) du ( at 1,59 } 2 ht & 3 re Here, 8) = C, 1) given, 2та со differentiate both side with respect tox, 3x+3yag Tr о с - 2 [ 'ха + ххаа dre 3. -50 * 84 — 2 — 21 Э dy ос dre ие. 9. E 9. - 3 » da (*-) 9.

Э dy de С 28-3х за-ук RP | С — 2-3 3-2 ы? dr (1») dy к ТС 1,5) Iry — - |

equation of fargent, (2-11) dre y-y,= dy at nigg, equation of tangent at (11) y-! = dy (x-1) dre |(1,1) → 4-1 = -1 (1-1) ☆ y - 1 = -7+1 y = -x +1+1 19- -x +2 Ay

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