Answers
We will use Fick's law of diffusivity for the question. All the numerical values have been aptly taken care of, along with dimensions. All the parts have been answered. Hope it helps.
Tick's first low, J = - Dac ax where I is the flex (moles m2 sec 2) Diffusivity of hydrogen and-irong D= Do e a where Do is constant o is activation energy Ris gas constant Tis temperature.
Is concentration x is thickness of wall Given that concentration of hydrogen within the vessel in contact with air can be taken O, - la = 4,2-0 =4.2moles in 3 Do= 0,1 mm² sec ² = 0,1x10 meseca &= 13,4 kJ mol = 134 Go Innol I R = 8,314 I mot kl T225°C = 298K ac = 4,2 moles m 4.2 moles in? 2x 4mm 4x103 m O/RT . Steady state flux, J = Do é ac P 6-13400 2 4.2 er 8,314x298J 4X203
= 1.05x16"exp (-5,4085) = 1.05x154x44783 x 103 = 4.7810 7 moles m? see a Moles through 1 m² in 1 see = 4,7X10 moles i. Moles through m 2 in 1 sec = 4.78107x2. moles Moles through 2 m² in 1 h (3600 sec) = 4,7x107x2X 3600 molos = 3,38 4 x 10s moles through 2m² - 2 Time taken to dissipate zo moles O moles 3,384X103 moles het - 5910 hr 1 omin It is possible to store hydrogengas in iron cylinders for very long time because hydrogenegas is essentially fly , which has negligible solubility in iron. Dissolved hydrogen embrittles &-iron (called hydrogen embrittlement) .
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It does so by reducing the energy required to generate new surfaces, thus making any fracture easier to occur.
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