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PLEASE ANSWER ALL OF THE QUESTIONS Question 9 2 pts Consider the two charges shown in...

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PLEASE ANSWER ALL OF THE QUESTIONS

Question 9 2 pts Consider the two charges shown in the drawing. Which of the following statements correctly describes the dirConsider the electric field lines, due to two charged particles A and B, shown in the drawing. Which of the following statemeIn the figure shown below, both the electric potential (42.1 volts) and the magnitude of the electric field at the yellow bal

Question 9 2 pts Consider the two charges shown in the drawing. Which of the following statements correctly describes the direction of the electric force acting on the two charges? 9, 92 The force on 91 points to the left and the force on 92 points to the right. The force on 91 points to the left and the force on 92 points to the left. The force on 91 points to the right and the force on 92 points to the left. The force on 91 points to the right and the force on 42 points to the right. There are no forces acting on 91 and 92 since they are both positive.
Consider the electric field lines, due to two charged particles A and B, shown in the drawing. Which of the following statements correctly describes this situation? B is a positively charged particle and A is a negatively charged particle. A and B are both positively charged particles. It indicates the relative magnitude of the electric field. A and B are both negatively charged particles. O A is a positively charged particle and B is a negatively charged particle.
In the figure shown below, both the electric potential (42.1 volts) and the magnitude of the electric field at the yellow ball (28.1 V/m) are indicated. Which one of the following equations correctly expresses the relationship between the electric potential, V, and the magnitude of the electric field, E? Notice that the distance between the point charges and the location of the yellow ball (the electric field) is approximately r= 1.50 m (150 cm). 42.4 V 0.1deg 28.1 Vim 150.3 cm OV= ! OV Er O r V= E E=Vr No answer text provided. Or=EV

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