## Answers

This is optics related problem.

As the fish sees from the aquarium then the light ray bends away from the normal.

Then the apparent distance is more than actual distance.

Then refractive index of the water in aquarium

is n = apparent distance / actual distance

apparent distance = 46 cm

n = 1.33 for water

Then 1.33 = 46 cm / actual distance

Then actual distance = 34.586 cm

.

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