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PART II: EXTRA CREDIT SHOW ALL WORK (10 points) te A 4.82-gram sample of a compound...

Question:

PART II: EXTRA CREDIT SHOW ALL WORK (10 points) te A 4.82-gram sample of a compound is dissolved in enough water to form 100.
PART II: EXTRA CREDIT SHOW ALL WORK (10 points) te A 4.82-gram sample of a compound is dissolved in enough water to form 100.0 mL of solution. This solution has an osmotic pressure of 25.0 torr at 25°C. If it is assumed that each molecule of the solute does not dissociate in this solvent, what is the molar mass of this solute? 2 mol n = 25 tom solute = 4,82g 7 = MRT V = nRT

Answers

Acconding to vaut Hobb equation , thie osmolic pressure is given by - = iMRT whene , IT = osmotie pressure (atm) i = vant H:: 3.289 x 10² atm = 1 XM mer- EP x 0.082057 Katm mot w x 298 K 7 M = 1,345x103 mol/L 1.345x1o mo? Now, 100 mL solution conta

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