need help with the calculatiobs the bottom picture is what i got performing the experiment C. Concentration Cells If both cell compartments contain copper metal and copper sulfate, the standard potential is 0.000 V and the Nernst equation becomes: Ercan = 0.000 volts (com dilute) volts Prepare a new cell, which has the beaker with 40 ml of 0.10 M CuSO. (from Part B) and 40 mL 0.0010 M Cuso. (from Part B) in an adjacent second one. Place copper strips in both solutions, provide a salt bridge and connect the clip leads to the strips. Read and record the voltage. Dilute the solution 0.0010 M copper(11) sulfate solution by another factor of 1 to 100 by solutions by performing a 1:100 serial dilution by making two consecutive 1:10 dilutions. First pipet 10.0000 mL of 0.0010 M stock solution into a 100.00 ml volumetric flask and bring it to volume with Na SO. This 1:10 dilution results in a 0.000100 M concentration. Repeat this by pipetting 10.0000 ml of the 0.000100 M solution into another 100.00 ml volumetric flask and bring to volume with Na SO - Add 40 mL of this 1.0 x 10M Cuso, solution to a new beaker adjacent to the first beaker already containing 0.10 M CuSO, solution. Reconstruct the cell using this solution and read the voltage. Part C. ANALYSIS & DISCUSSION Do the calculations below and use/answer the following questions in your discussion. Remember to use the T you measuredi 1. What is the theoretical cell Voltage, Ecal and Ecell values, for each of the cells above? What is the percent error of your experimental results? Suggest why the results deviate from theory. 2. What effect did diluting the solution in the second microcell have on the measured cell voltage? 3. Considering the first cell prepared above, what would happen to the measured cell voltage if the solution in the first microcell were now diluted by a factor of 1 to 100? Show a calculation to justify your answer. 4. Calculate AG and AG for each cell using the values of E and E. From (1) above using the Nernst equation. 5. What does this experiment suggest about the relation between equilibrium and cell potential part of 34:4 у hq: 5V

E O.00- иF R = 8.310 Tempe vafare n voy Impor tut Factor slich i not moleuc ya Con sidu 2sc Conved to k yaur &ubin 25+273. F- 96500 T: 298 k Calalali RT 8.314X298 O.0257 F 96500 Sub sttute u Aboue eauabu yau get 9.0257 t2 dil Eall volb lat Cone IO.128s lu O.001 Ea0-128) 605) C0 E all -0.59.17 Volt Eal -o.28s) n 1X10 -001285) L O.0oco fo./235)Ca.2103 Eall lO18 V .

Need help with the calculatiobs the bottom picture is…

Answers

E O.00- иF R = 8.310 Tempe vafare n voy Impor tut Factor slich i not moleuc ya Con sidu 2sc Conved to k yaur &ubin 25+273. F-

Similar Solved Questions

1 answer

P3. In a hydrogen atom in its lowest energy state (known as the ground state), the...

P3. In a hydrogen atom in its lowest energy state (known as the ground state), the electron forms a spherically-symmetric "cloud" around the nucleus, with a charge density given by ρ-A exp(-2r a ), where a,-0.529 Â-0.529 × 10-10 m is the Bohr radius. (a) Determine the constan...

Need help with the calculatiobs the bottom picture is what i got performing the experiment C....

Question:

Answers

Similar Solved Questions