Magnetic Fields due to Currents in 4 wires

We'll use Biot-Sevart law:

and in our case:

B*2πr=μ₀*I

r is the distance between each wire and the canter of the square being equal to sqrt(13²+13²)=13*sqrt(2) and I being the current.

so we get:

B=μ₀*24/(2*0.26π)=600μ₀/13π

This is the magnetic field each wire generates. the direction is according to the right hand rule.

so if the qires are positioned:

1 2

3 4

Then the magnetic field in the midle is zero since 1 and 4 cancel each pther out and 2 and 3 also cancel out.

If the wires are:

1 2

4 3

then the magnetic field is 4*B=2400μ₀/13π and the direction is from the center toward wire number 4.