## Answers

Reading in blood glucose meter is 385 mg/dL

= 385 × ( 10^{-3} g/10^{-1} L)

= 3.85 g/L

Now molecular weight of glucose=180

So no of moles of glucose per litre = (3.85/180)

=0.0214

So concentration of glucose = 0.0214 M

= 0.0214 × 10^{3} mM

= 21.4 mM

2. As the reaction has occured over 30 minutes so rate of reaction

= Change in concentration/ time

= (21.4/30)mM/min

=0.7133 mM/min.

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