1 answer

Just type the answers, thank you for the help, i appreciate it 1 point) Archeologists have...

Question:

just type the answers, thank you for the help, i appreciate it
1 point) Archeologists have discovered a sample of ancient Egyptian skulls from two different time periods, 4000 B.C. and 150
4000 B.C. mean: 127.25 150 A.D. mean: 134.50 4000 B.C. standard deviation: 5.2847 150 A.D. standard deviation: 4.7809 Part 2:
1 point) Archeologists have discovered a sample of ancient Egyptian skulls from two different time periods, 4000 B.C. and 150 A.D. They believe that the mean maximum skull breadth (the width of the skull at its widest part) has increased from 4000 B.C. to 150 A.C.A sample of 13 Egyptian skull breadths (in mm) from each time period is show below: 4000 B.C. 118, 125, 134, 129, 122, 129, 132, 129 150 A.D. 132, 131, 137, 140, 142, 134, 132, 128 Part 1: Calculate the mean and standard deviation for each data set. Round each mean to 2 decimal places, and each standard deviation to 4 decimal places. 4000 B.C. mean: 127.25 150 A.D. mean: 134.50 4000 B.C. standard deviation: 5.2847 150 A.D. standard deviation: 4.7809 - Part 2 Using your answers from part 1 and the formula for a 95% confidence interval as presented in lecture, fill in the blanks with the appropriate values for this problem for calculating the confidence interval below. To enter V where x is any number, type sqrt(x). For example, 2 should be written as sqrt(2) 4000 B.C. skull breadths:
4000 B.C. mean: 127.25 150 A.D. mean: 134.50 4000 B.C. standard deviation: 5.2847 150 A.D. standard deviation: 4.7809 Part 2: Using your answers from part 1 and the formula for a 95% confidence interval as presented in lecture, fill in the blanks with the appropriate values for this problem for calculating the confidence interval below. To enter x where x is any number, type sqrt(x). For example, V2 should be written as sqrt(2). 4000 B.C. skull breadths: to 150 A.D. skull breadths: to

Answers

Given:

A sample of ancient Egyptian skull breadths from two different time periods( 4000 B.C and 150 A.D) is given.

Sample size = n =13

Time Period Mean Standard deviation
4000 B.C 127.25 5.2847
150 A.D 134.50 4.7809

The 95% confidence interval is given by

\bar{X}\pm(\frac{Z*s}{\sqrt{n}})

where, Z = 1.96

The 95% confidence interval for 4000 B.C skull breadths:

127.25\pm(\frac{1.96*5.2847}{\sqrt13}) = 127.25\pm2.87=( 124,130)

The 95% confidence interval for 150 A.D skull breadths:

134.50\pm(\frac{1.96*4.7809}{\sqrt13}) = 134.50\pm2.6=( 132, 137)

.

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