Answers
Solution
P(A) = 0.02, P(B) =0.05
P(A') = 0.98, P(B') = 0.95
So P(A' intersection B') = P(A') * P(B') = 0.98*0.95 = 0.931
So there is 93.1 % chances that an article is free or both kind of defects.
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