Answers
If D: Lamp is defective. Given PIA)-20%= 0.2, PCB): 30%=0.3, P(c)=50% =0,5 Also P(DIA): 1%-0.01, P(DIB):0.04, PCDIC):0.07 P(Damaged): PCD)=P(PNA) +P(DNB)+P(DNC) = P(DIA) PCA) + PDB) PCB) +PCDIC) Ple) -0.01)(0.2)+(0.04)(0,3)+(0.07)(0.5) -0.049