1 answer

In an ice show a 65.0 kg skater leaps into the air and is caught by...

Question:

In an ice show a 65.0 kg skater leaps into the air

In an ice show a 65.0 kg skater leaps into the air and is caught by an initially stationary 70.0 kg skater. (a) What is their final velocity assuming negligible friction and that the leaper's original horizontal velocity was 4.00 m/s? (b) How much kinetic energy is lost? J

Answers

(a) required velocity = [65/(65+70)] x 4

                                 = 1.925 m/s

(b) energy loss =1/2(mv2-Mv2)

=1/2[(80x4x4)-(135x1.925x1.925)]

= 389.87 J

.

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