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I l l I G The Law Magnitude что А en Triangle OBD BD = D. xá a Anitally due to all the other two arme the Magnen Let the triangle is carrying current in clockwise duuction Magnitude of current I = 1 {riven] g Mgnetic field Using Biot savart a finite Wire as given Ba Mo I [ smo,+ sino,] Z BOD= 60° = 2 So tan 60° - 1 / uring the Right hand Rule The direction netic field due AC at centore 0. thumb point towards the current direction then the curled fingers will represent the direction of Magnetic field feld will be downwards a - l a tan 60° 253 Now, Using of Magnet downwards of the B
so Net Magnetic field = Magnehr freld due to CAB + BC + CA) - BAB + BBL + BCA since same - I a & Q o for all are Net Š 3BAR =3[ Mo I (son 0, +5110,) smo, Un a Here a= l I I 0,- 0,= 60° 1 So Net ol triangle 3 magnetic netic Field at the centre of equilatual (sin 600+ stn 60) 2x ] lo 1 un e 2.13 3 ملل ( X 2X 3 لا une 253 - -31 Mo 3 2ñe 3] 9 Mo ans 2 Te And duection is downwards into the paper
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