1 answer

If a projectile is shot at an angle of #(pi)/8# and at a velocity of #17 m/s#, when will it

Question:

If a projectile is shot at an angle of #(pi)/8# and at a velocity of #17 m/s#, when will it reach its maximum height?

Answers

#t_m=0,6632 s#
#h_m=2,1564 m#

Explanation:

#alpha=pi/8*180/pi=22,5^o#
#t_m=v_i*sin alpha/g#
#t_m=17*sin (22,5)/(9,81)#
#t_m=0,6632 s" elapsed time to reach maximum height"#
#h_m=(v_i^2*sin^2 alpha)/(2*g)#
#h_m=(289*0,1464)/(19,62)#
#h_m=2,1564 m " maximum height"#

.

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