1 answer

I want to see the thought process behind this so that I could approach similar problems...

Question:

8. Coin 1 and Coin 2 are biased coins. The probability that tossing Coin 1 results in head is 0.3. The probability that tossing Coin 2 results in head is 0.9. Coin 1 and Coin 2 are tossed. (i) What is the probability that the result of Coin 1 is tail and the result of Coin 2 is head? (ii) What is the probability that at least one of the results is head? (ii) What is the probability that exactly one head appears? iv) What is the probability that the result of Coin 1 is head given that exactly one head appears?I want to see the thought process behind this so that I could approach similar problems on my own, so please attempt to show every step and formula used, thank you.

8. Coin 1 and Coin 2 are biased coins. The probability that tossing Coin 1 results in head is 0.3. The probability that tossing Coin 2 results in head is 0.9. Coin 1 and Coin 2 are tossed. (i) What is the probability that the result of Coin 1 is tail and the result of Coin 2 is head? (ii) What is the probability that at least one of the results is head? (ii) What is the probability that exactly one head appears? iv) What is the probability that the result of Coin 1 is head given that exactly one head appears?

Answers

Coin i and Coin 2 are biased Coins The Probability that tossing Coin i tesuls n head is o 3 iven Thet > ) Probability that the tesult op Coin i is tail and the tesult of Coin 2 is head i) Probability atat least one of the tesults 1-p (both aretails is head > עו probabilty that exactly one head appeaes - p (coin head and Coin 2 tail) P(Coin L tai and Coin 2 heads) iy) Prrobabily that the tesut oP coin i is head given that head appears exactly once p(coin1 head and 2 tails) Plexactly head ) 0 0455

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