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In series R C circuit While charging = v (t) = v_0 (1 - e^t/T) Discharging = v (t) = v_0 e^- t/T T . R C Given data c = 10 mu F v = 20 v R = 3.3 k ohm Discharging voltage across ' C ' after 20 m sec T = Time constant = R C = (3.3 k) (10 mu) = 33 times 10^- 3 sec Therefore V (t) = v_0 e^- t/T = 20 e ^- 20 times 10^- 3 /33 times 10^- 3 = 20 e^- 2 0/33 = 20 (0.5454) v(t) = 10. 909 v Now I (t) = V/R (1 - e^- t/T)

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