1 answer

How many moles of lithium hydroxide would be required to produce 89.5 g of li2CO3 in...

Question:

how many moles of lithium hydroxide would be required to produce 89.5 g of li2CO3 in the following chemical reaction 2Lioh+co2=li2Co3+H2o


Answers

Holes of his co3= weight of Lięcon o Molar mass of Lig Co (g/ rave 89.59 73.891 g/ role - 1.211 roles of Lizeon2.422 roles of Ligh produced 89.5 g of Liz Coz. & Liot + Cog 9 Ligcozt H₂o I roles of high (2X23.959) produces I tole of Lig

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