1 answer

How do you write #sec(2x)# in terms of sinx?

Question:

How do you write #sec(2x)# in terms of sinx?

Answers

#sec(2x) = 1/(1 - 2sin^2(x))#

Explanation:

#sec(2x) = 1/cos(2x) = 1/(1 - 2sin^2(x))#

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