1 answer

How do you write a balanced equation for acid-base reactions?

Question:

For example:
#LiOH + HNO_3# #H_3PO_4 + KOH# #Ca(HCO_3)_2 + HCl# #Ba(OH)_2 + H_2SO_4# #MgCO_3 + HNO_3#


Answers

If we represent the acidium species as #H^+#, we have:

#H^+ + HO^(-) rarr H_2O(l)#

Explanation:

And thus:

#LiOH(aq) + HNO_3(aq) rarr H_2O(l) + LiNO_3(aq)#

#H_3PO_4(aq) + KOH(aq) rarr KH_2PO_4(aq) + H_2O(l)#

#Ca(HCO_3)_2(aq) + 2HCl(aq) rarr CaCl_2(aq) +2H_2O(l) + 2CO_2(g)uarr#

#Ba(OH)_2(aq) + H_2SO_4(aq) rarr BaSO_4(s)darr +2H_2O(l)#

#MgCO_3(aq) + 2HCl(aq) rarr MgCl_2(aq) +H_2O(l) + CO_2(g)uarr#

Are these balanced? Don't trust my arithmetic.

.

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