1 answer

How do you solve #-x- 29= 13+ 2x#?

Question:

How do you solve #-x- 29= 13+ 2x#?

Answers

See the entire solution process below:

Explanation:

First, add #color(red)(x)# and subtract #color(blue)(13)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-x - 29 + color(red)(x) + color(blue)(13) = 13 + 2x + color(red)(x) + color(blue)(13)#

#-x + color(red)(x) - 29 - color(blue)(13) = 13 - color(blue)(13) + 2x + color(red)(x)#

#0 - 42 = 0 + 3x#

#-42 = 3x#

Now, divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:

#-42/color(red)(3) = (3x)/color(red)(3)#

#-14 = (color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3))#

#-14 = x#

#x = -14#

.

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