1 answer

How do you solve #(2 (tan^2)x - 1)((tan^2)x +1) = 0#?

Question:

How do you solve #(2 (tan^2)x - 1)((tan^2)x +1) = 0#?

Answers

Solve #(2tan^2 x - 1)(tan^2 x + 1) = 0#

#x = +- 35^@18 + kpi#

Explanation:

The quantity (tan^2 x + 1) > 0 regardless of values of x.
(2tan^2 x - 1) = 0
#tan^2 x = 1/2#
#tan x = +- sqrt2/2#
a. tan x = sqrt2/2 --> arc #x = 35^@18 + kpi#
b. tan x = -sqrt2/2 --> arc x = - 35*@18 + kpi

.

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